Travis Taylor (MIN) vs. Seattle this week
Troy Williamson (MIN) vs. Seattle this week
Eric Parker (SD) vs. Kansas city this week
2006-10-21 05:36:01 · 8 answers · asked by j c 2 in Sports ➔ Fantasy Sports
Go with Williamson this week and depending on how he does, maybe in the future. Minnesota is a team that will only get better as the year goes on.
2006-10-21 05:41:18 · answer #1 · answered by cubswin03 3 · 0⤊ 0⤋
Id go with Eric Parker I guess. None of them are really gonna do much but I think that Eric might have the better potential in those match ups.
Kansas City is notoriously bad in the secondary and the talk all week here has been about shutting down LT so I think the passing game will be open for the bolts. I live in KC, so you hear things.......ya know?
2006-10-21 05:44:28 · answer #2 · answered by TheTruthHurts 3 · 0⤊ 0⤋
%. up Henne,Cutler, and Alexander.launch Jackson,Amendola, and Barber.Barber isnt extremely used for Cowboys.Theyre utilising Felix Jones greater in lots of cases to attack.Cutler for valuable.Alexander had a great interest and Amendola didnt.Dont anticipate something from Jackson.Henne ought to be picked up if youd like yet another QB.you are able to grab Ivory yet hes no greater effective than Rice and Jones.i wish this could help. :)
2016-11-24 21:15:59 · answer #3 · answered by papke 4 · 0⤊ 0⤋
Rivers is getting more and more comfortable with every start. I would have to say Eric Parker.
2006-10-21 05:40:54 · answer #4 · answered by Willie 2 · 0⤊ 0⤋
i think the chargers move the ball i see 37-7 parker could see 80 yds and a possible score.
2006-10-21 05:53:16 · answer #5 · answered by letitbemetheone 3 · 0⤊ 0⤋
Seattle doesn't even have an NHL team.
2006-10-21 05:39:11 · answer #6 · answered by Anonymous · 0⤊ 0⤋
since seattle is very good, i would recommend eric parker. oh yeah BOO STEELERS
2006-10-21 05:43:01 · answer #7 · answered by ASK 3 · 0⤊ 0⤋
TAKE ASHELY LIELIE FROM THE FACLONS MIKE IS GOING TO BE THROWING THAT ***** THIS WEEKEND
2006-10-21 05:39:31 · answer #8 · answered by Anonymous · 0⤊ 0⤋