Input three numbers.
Declare a variable 'small'(stores the smallest number) and assume that small = number1
if(number2
small = number2;
if(number3 < small)
small = number3;
Print - "The smallest number is" small;
I hope you can convert this into a proper C++ program, I am not very good at algorithms.
2006-10-20 22:41:59
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answer #1
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answered by Anonymous
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Declare your set of 3 number as A, B and C, and Min as variables
To make sure that one number amongst 3 is the smallest you have to compare it to the other 2
Naming A is the smallest if and only if A
so your code should be something like that
If A < B And A < C Then
Min =A
ElseIf B < A And B < C Then
Min = B
ElseIf C < B And C < A Then
Min = C
End If
(in vb syntax)
2006-10-21 00:02:12
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answer #2
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answered by Anonymous
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ermm.... I no longer an issue-unfastened programmer... so i will write in PASCAL langugage....... var a:array[a million..3] of integer; {that's the variable assertion} n,i,max:integer; initiate jointly as n<>3 do initiate inc(i); readln(a[i]); inc(n); end; {that's the enter section} for i:= a million to 3 do initiate if a[i]>max then max:=a[i]; {that's the looking algorithms} end; writeln(max); {that's the OUTPUT/PRINT section} end; wish it enables peace vixklen
2016-11-24 20:54:58
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answer #3
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answered by saragosa 4
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It's dead easy in Python:
s = [1,12,5] # for example
s.sort()
s[0] # returns 1, the minimum value
s[-1] # returns 12, the maximum
2006-10-21 00:37:30
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answer #4
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answered by poorcocoboiboi 6
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You could actually do this in one line of code using a couple ternary operators in Java or C#, or anything that supports ( ? : )
2006-10-21 01:54:36
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answer #5
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answered by Dr.Mr.Ed 5
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let the three numbers are a,b,c.
"small" is avariable to hold smallest value.
if((a
small= c;
else
{
if((b
small=b;
if((c
small=c;
}
2006-10-20 23:47:32
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answer #6
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answered by indian 2
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hmmm smalles 3 digit number uhh how about.....000?
2006-10-20 22:40:19
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answer #7
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answered by sslender9 3
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