What is the number that increased by one sixth of itself and yields 182?

Answer 1

156

Answer 2

Let

x = the number

1/6x = the amount of increase of itself

182 = the yield

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x + 1/6x = 182

6(x) + 6 (1/6x) = 6(182)

6x + 6/6x = 1092

6x + x = 1092

7x = 1092

7x/7 = 1092/7

x = 156

The answer is x = 156

Insert the x value into the equation

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Check

x + 1/6x = 182

156 + 1/6(156) = 182

156 + 156/6 = 182

156 + 26 = 182

182 = 182

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Answer 3

x + x/6 = 182 => x = 182/(7/6)
therefore x=156

Answer 4

Let the number be x.

Equation: x+x/6=182 (multiply both sides by 6 so that fractions
will be eliminated)
6(x+x/6)=182(6)
6x+x=1092
7x=1092
7x/7=1092/7
x=156

The number that you are looking for is 156.

Answer 5

assume the number is X then, X+X/6=182
(7/6) X =182
X = (6/7) 182
X = 156

Answer 6

1)
(7/6)x = 182
2)
6*182/7=156

Answer 7

156.

suppose x is the number.

now x is increased by 1/6th ,
so it will be 1/6*x

above both yeilding 182.
LET US COMBINE ABOVE ALL:

x+(1/6)*x=182
x(1+ 1/6)=182
x(6+1 / 6 )=182
x(7/6)=182
x=182*6/7
x=26*7*6/7
x=26*6
x=156

Answer 8

156

Answer 9

Let x = the number.
One sixth of this number is x / 6.
Therefore the equation you need to solve is:
x + x / 6 = 182
See how you go.

Answer 10

Whewww... (That was the sound of this question flying high above my head.) ... Lol... I'm an English major, but I totally admire you people who understand this stuff! :)