I have a maths question.?

Question

My daughter came home with a question that I have no idea how to help her with. Her math teacher asked the class to work out:

A farmer has 10 sows. Each sow had 14 piglets, 7 of which were sows. How many pigs will he have in 5 years? Indicating working out would be greatly appreciated. I assume each sow gives birth to 7 sows and 7 hogs.

Thanks guys but I think that somewhere in there is exponential growth ie: each of the seven sows has another 14 piglets ect.

Its for high school, Year 10.

There were 10 sows and they gave birth to 14 piglets, seven of which were sows and seven of which were hogs.

I assume that every year the sows birth 7 S's and 7 H's.

Answer 1

This is a very poorly worded question. Do we assume the pigs breed annually?

P = M + S

total pigs = males + sows (forget the little play on words with the initials!)

I would suggest just making a table, years versus pigs.

Years Pigs
--------------
....0......10 (original number)
....1......70 + original 10 = 80
....2.....560 + 80 from previous year = 640
....3....4480 + 640 from previous year = 5120
....4...35840 + 5120 from previous year = 40960
....5..286720 + 40960 from previous year = 327680

Just so you know, the 70, 560, 4480, etc...

...come from the number of piglets the sows birth from the previous year. Example: after year 1, you have 80 pigs, 40 of which our sows.

So 40 * 14 = 560

And then you add the number of pigs in year 1 to that to find the year 2 total.

I'm assuming no pigs die.

I wouldn't even try to make an equation (exponential or otherwise) out of this. If you want to, knock yourself out!

Holy pigs. I teach high school math...and I would hesitate to assign this kind of problem!

EDIT:

Just looked at your profile and questions asked, and the question about the car at the speed of light is wrong, I believe.

Einstein thought of this kind of issue when developing his theories on gravitation, and after much mathematics, determined that the speed of light is "invariant", meaning unchanging. In fact, he wanted to call his theory not the Theory of Relativity, but the Theory of Invariance.

What it means is that no matter how fast or slow your velocity, the speed of light from your perspective is always CONSTANT.

So the light from your headlights would race away at the speed listed in the textbooks.

Of course, it is a highly theoretical question anyways, as ANYTHING with mass CANNOT travel at the speed of light...another little tidbit Einstein formulated!

enjoy!

BIG EDIT!!

OOPS!!

Lisaloo caught something I missed. If all the pigs were originally sows, then her answer is good. I didn't catch that...I assumed there were 5 sows to start with. Now, here is another problem with this problem, are there only the 10 pigs, all sows, to start with?

OR, are there 10 males also, or 20 total pigs to start with.

You know, if I were you, I would send this question back to the teacher and ask that if s/he wants to assign interesting thought problems, that is fine, but ALL of the pertinent information needs to be provided!

Answer 2

Are we to assume that the sows that have piglets the first year are also having piglets each year of the 5? And how soon can a piglet sow have their own piglets? I agree that this is a terribly worded question.

Year One
10 sows * 14 each= 140 new pigs + 10 original pigs= 150

Year Two
80 sows * 14 each= 1120 new pigs + 150 =1270

Year Three
640 sows * 14 each= 8960 new pigs + 1270 = 10,230

Year Four
5120 * 14 each = 71,680 new pigs + 10,230 =81,910

Year Five
40,960 *14 each= 573,440 new pigs + 81,910 = 655,350

What grade is this problem from? And why in the world would someone need to have 655,350 pigs?????

Answer 3

each sow will have 14 pigletts every year. so
10 x 14 = 140
14 x 5 (years) = 70
140 x 70= ur answer


idk how i got that but i think it is right

wait...thats wrong

10 x 14 = 140
7 x 5 (years) = 35
140 x 35= ur answer

Answer 4

no of sows=10
piglets/sow=14
total no of piglets=14*10=140
no os sows/piglets=7/14
no of pigs/piglets=(14-7)/14=7/14
no of pigs=half the nof of piglets=70

Answer 5

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Answer 6

10*7=70 gurls pigs
10*7=70 boys pigs

70*7=490/2=245(one year)*7=x/2=z(2 years)*7=c(3 years)/2=b(4 years)*7=h(5 years)

h * 2 == the answeer

Answer 7

heh a lot going there =P

10 times 14 = 140

140 times 5 = 700

so i think we will have 700 pigs in 5 years

well i hope this helped.