What is the calculus behind the commutative relationship of angular momentum [LxLy] = i(hbar)Lz where
Lx = -i(hbar)(yd/dz - zd/dy)
Ly = -i(hbar)(yd/dz - zd/dy)
Lz = -i(hbar)(xd/dy - yd/dx)
2006-10-20 14:42:13 · 2 answers · asked by nathaniel49 2 in Science & Mathematics ➔ Mathematics
Its algebra not calc...sorry
2006-10-20 15:11:24 · update #1
You mean commutator, not commuter. Mostly, you just have to use the product rule. Apply your operators to a function and simply evaluate
[Lx,Ly]f=Lx (Ly f)-Ly (Lx f).
It turns out that all the second derivatives cancel out and you get that
[Lx,Ly]f=i(hbar)Lz f.
2006-10-21 04:43:10 · answer #1 · answered by mathematician 7 · 0⤊ 0⤋
I thought it was a question about taking the train in NYC before I clicked on it. Im sorry I totally failed calculus
2006-10-20 21:49:56 · answer #2 · answered by nylatinanurse 5 · 0⤊ 0⤋