My algrbrator will do square roots, but I am having a hard time putting in the information where it actually looks correct.
Square root 2t^5 * Square root 10^4
and
(3 - 2 Square root 7)(3 + 2Square root 7)
I have a whole bunch to try to solve, and if I can get the idea, I think I can finish all the other ones myself.. can someone help?
2006-10-20 13:53:30 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
sqrt(2t^5)*sqrt(10^4)
= (2t^5)^(1/2) * (10^4)^(1/2)
= 2^(1/2) (t^5)^(1/2) * (10^4)^(1/2) (using (ab)^x = a^x b^x)
= sqrt(2) t^(5/2) 10^2 ( using (a^x)^y = a^(xy) )
= 100sqrt(2) t^(5/2)
(3 - 2*sqrt(7))(3 + 2*sqrt(7)):
Use the formula (a+b)(a-b) = a^2 - b^2:
3^2 - (2*sqrt(7))^2 = 9 - 2^2*(sqrt(7))^2 =
9 - 4*7 = 9 - 28 = -19.
2006-10-20 13:59:58 · answer #1 · answered by James L 5 · 0⤊ 0⤋
√(2t^5) = (2t^5)^.5 = (2)^.5 * (t^5) = √2 * t^2.5
√(10^4) = (10^4)^.5 = 10^2
(3-2√7)*(3+2√7) = (3)^2 - (2*√7)^2 = 9 - 4*7 = 19
2006-10-20 13:59:38 · answer #2 · answered by gp4rts 7 · 0⤊ 0⤋
sq. room 3 minus sq. root 2 divided by way of sq. root 6 9-4 ____ 36 5/36 thats greater effective than a million over sq. root 2 minus a million over sq. root 3 uncertain the cost yet its much less
2016-11-24 20:30:00 · answer #3 · answered by magoon 4 · 0⤊ 0⤋
These are algebra questions .You should not be using a machine for this.
2006-10-20 14:03:38 · answer #4 · answered by sydney m 2 · 0⤊ 0⤋
on your calculator, everywhere u can put paranthesis, use them. Only advice there is
2006-10-20 13:57:08 · answer #5 · answered by sur2124 4 · 0⤊ 0⤋