lim x-> -3- h(x)=?

0 ⤊

suppose you know that h is an odd function, and that lim x->3+ h(x)=-5

2006-10-20 13:14:12 · 4 answers · asked by MJ 1 in Science & Mathematics ➔ Mathematics

odd function: h(-x) = -h(x)
lim x->3+ h(x) = lim x->3- h(-x) = -lim x->3- h(x) = --5 = 5

2006-10-20 13:24:15 · answer #1 · answered by sofarsogood 5 · 0⤊ 0⤋

Well an odd function is a function such that f(-x) = - f(x)

Thus lim x -> -3 (- h(x)) = lim x -> -3 (h (-x))

= lim x -> +3 (h(+x))

= - 5

2006-10-20 20:20:47 · answer #2 · answered by Wal C 6 · 0⤊ 0⤋

like they said -5

2006-10-20 20:40:59 · answer #3 · answered by Rex 4 · 0⤊ 0⤋

i know but what about that your giving the answer =negative 5

2006-10-20 20:16:49 · answer #4 · answered by coolasty 2 · 0⤊ 0⤋