At a party, there was one pizza for every 3 people, one salad for every 6 people, and one cake for every 8 people. If the total number of pizzas, salads, and cakes was n, in terms of n, how many people were at the party?
2006-10-20 12:49:31 · 6 answers · asked by liquid_force_evolution 2 in Science & Mathematics ➔ Mathematics
Let P = no of people at party, p = no of pizzas, s = no of salads and c = no of cakes
Thus p = P/3, s = P/6 and c = P/8
Thus P/3 + P/6 + P/8 = n
ie (8P +4P + 3P)/24 = n
Thus 15P = 24n
ie P = 24n/15
= 8n/5
2006-10-20 12:56:23 · answer #1 · answered by Wal C 6 · 1⤊ 0⤋
Let P be the number of pizzas, S be the number of salads, and C be the number of cakes. Also, let N be the number of people.
Then P=N/3, S=N/6, and C=N/8.
Also, N/3+N/6+N/8 = n. Therefore,
n = N(1/3+1/6+1/8) = N(8/24+4/24+3/24) = N(15/24) = 5N/8, so N=8n/5.
2006-10-20 12:54:34 · answer #2 · answered by James L 5 · 1⤊ 2⤋
8(n/5)
2006-10-20 13:05:41 · answer #3 · answered by beatrice_africa 2 · 0⤊ 0⤋
Pizza? am I invited?
2006-10-20 13:00:22 · answer #4 · answered by matt 1 · 1⤊ 0⤋
All I know is now I'm hungry.
2006-10-20 12:56:56 · answer #5 · answered by loon_mallet_wielder 5 · 1⤊ 1⤋
holy crap i remember that EXACT problem but never learned how to do it
2006-10-20 12:53:21 · answer #6 · answered by Anonymous · 1⤊ 2⤋