Do you mean sina = 5/13?
If you do then sin 2a = 2sin a . cos a
sin² a + cos² a = 1
cos² a = 1 - sin² a
= 1 - 25/169
= 144/169
So cos a = ±12/13
Since a is a 2nd quadrant angle cos a <0
Thus cos a = -12/13
Thus sin 2a = 2 . 5/13 . -12/13
= -120/169
2006-10-20 12:45:08
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answer #1
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answered by Wal C 6
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Given Sin a = 5/13 and a is in quadrant 2 tells that Cos a = -12/13
Note Quad 2 Sin is +ve and Cos and Tan are -ve. Recall that 5 12 13 form a Pythagorean triple and so form a RIGHT ANGLED TRIANGLE.
Now
Sin 2a = 2 Sina Cos a
= 2 5/13 -12/13
= -120/169
2006-10-20 12:46:39
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answer #2
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answered by Anonymous
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I assume you mean "sin a = 5/13".
a is in quadrant II, so pi-a is in quadrant I. Let a'=pi-a. Since sin(a') = sin(a), it follows that a' is the angle of a right triangle, with the ratio of the side opposite a', which I'll call O, to the hypotenuse, H, being 5:13. We then assume that the lengths of these sides are O=5 and H=13.
By the Pythagorean Theorem, the length of the side A adjacent to angle a' satisfies O^2 + A^2 = H^2. Plug in O=5 and H=13, and you get
5^2 + A^2 = 13^2
=> 25 + A^2 = 169
=> A^2 = 144
so A = 12.
By SOHCAHTOA, cos(a') = A/H = 12/13.
sin(2a') = 2*sin a'*cos a'. Therefore, sin(2a') = 2*(5/13)*(12/13) = 120/169.
Finally, sin(2a) = sin(2(pi-a')) = sin(2pi-2a') = -sin(2a') = -120/169.
This comes from the fact that sin(2pi+x) = sin(x), and sin(-x) = -sin(x).
2006-10-20 12:43:17
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answer #3
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answered by James L 5
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Do mean sina 5/13
sin 2a = 2sin a . cos a
sin² a + cos² a = 1
cos² a = 1 - sin² a
= 1 - 25/169
= 144/169
cos a = ±12/13
2nd quadrant angle cos a <0
cos a = -12/13
sin 2a = 2 . 5/13 . -12/13
= -120/169
2006-10-20 12:46:01
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answer #4
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answered by Anonymous
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I'm assuming that you meant sin a = 5/13.
Okay, here's the easy way...
sin a = 5/13
Take the arcsin to determine a...
a = acrsin(5/13) = 22.62 degrees.
However, the problem says that a is in quadrant II. A as solved above is in quadrant I. Therefore, we need to find the angle in quadrant II that corresponds to 22.62 degrees.
a = 180 degrees - 22.62 degrees = 157.38 degrees
Now, we can determine what the sin of 2a is...
sin (2a) = sin (2*157.38) = -0.71
2006-10-20 12:50:47
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answer #5
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answered by Josh 2
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sin2a=2sina cosa
given sina=5/13
so cosa =12/13
sin2a=2(5/13)(12/13)
=120/169
it is ih the first quadrant
2006-10-20 12:44:15
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answer #6
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answered by raj 7
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