The volume of the box is represented by (x^2 + 5x + 6)(x + 5). Find
the polynomial that represents the area of the bottom of the box.
2006-10-20 12:26:25 · 5 answers · asked by klickie 2 in Science & Mathematics ➔ Mathematics
This question came up before and it isn't any clearer now than it was then.
x^2+5x+6 factors into (x+2)(x+3), so the volume can be written as
(x+2)(x+3)(x+5).
Therefore, it's likely (but not certain!) that the dimensions of the box are x+2, x+3 and x+5. However, it is not stated which of these are the length, width, and height, respectively. Therefore, assuming these really are the dimensions, there are 3 possible answers for the area of the bottom:
(x+2)(x+5)
(x+3)(x+5)
(x+2)(x+3)
2006-10-20 12:31:53 · answer #1 · answered by James L 5 · 2⤊ 0⤋
Volume = L * W * H
= (X^2 + 5x + 6) * (x + 5)
= (x + 3) (x + 2) * (x + 5)
Now the above statement represents each side respectively LWH
The area of the bottom of the box is L * W the difficulty is in deciding which is which.
but i think the area would be the first polynomial given
x^2 + 5x + 6
2006-10-20 20:36:48 · answer #2 · answered by jamnad 1 · 0⤊ 0⤋
Assuming that the dimensions of the box are the factors of the final polynomial,
V = (x+2)(x+3)(x+5)
With the height unspecified, you have 3 possible answers:
A = (x + 2)(x + 3) = x^2 + 5x + 6, h = x + 5
A = (x + 2)(x + 5) = x^2 + 7x + 10, h = x + 3
A = (x + 3)(x + 5) = x^2 + 8x + 15, h = x + 2
If the height is something else, then none of these answers is correct.
2006-10-20 19:41:37 · answer #3 · answered by Helmut 7 · 0⤊ 0⤋
(x+3)(x+2)(x+5)=volume
since volume =area of cross section *height
x^2+5x+6 can be taken as the area of cross section and (x+5) as the height
2006-10-20 19:30:00 · answer #4 · answered by raj 7 · 0⤊ 0⤋
x^2+5x+6
2006-10-20 19:31:27 · answer #5 · answered by Nobody 3 · 0⤊ 0⤋