multiplication expression showing work?

Question

-2a^2/3a^2 * 20a/15a^3

Answer 1

Hi Dear Schnitzel ;

{ as you know If
(a ^ n) * ( a ^ m ) = a ^ ( n +m)
(a ^ n) / ( a ^ m ) = a ^ ( n - m)
a ^ 0 = 1
a ^ -n = 1 / ( a ^n ) } ....

we have ;
(-2 a^2) / (3 a^2) * (20 a) / (15 a^3 )

• Part 1
(-2 a^2) / (3 a^2) =
(-2/3)( a ^ ( 2 - 2)) =
(-2/3)( a ^ 0 ) =
(-2/3) * 1 =
-2/3

• Part 2
(20 a) / (15 a^3 )=
(20/15) * ( a / ( a ^3 )=
(4/3) * ( a ^ ( 1 - 3)) =
(4/3) * (a ^ -2)=
4/( 3 a^2)

• Part 3
( -2/3 ) *( 4/( 3 a^2)) =
( -2 * 4 ) / ( 3 * 3 a^2) =
-8 / (9 a^2)


Good Luck Dear....

Answer 2

Assume you want to multiply the two fractions

(-2a^2/3a^2)(20a/15a^3)

Did you really have a^2 in both the numerator and denominator of the leftmost fraction?

(-2/3)(20/15a^2)
(-2/3)(4/3a^2)
-8/9a^2

Answer 3

In the left fraction, the a² cancels out.
-2/3 * 20a/15a³

Similarly in the right fraction, you can cancel 5a from top and bottom.
-2/3 * 4/3a²

Now multiply across (numerators, then denominators)
-8 / 9a²

There's your answer.