18*35=630
630/30=21
21-18= your answer
2006-10-20 11:38:42
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answer #1
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answered by VantheMan 3
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3
2006-10-20 11:54:24
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answer #2
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answered by rooboy232002 2
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3
2006-10-20 11:42:56
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answer #3
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answered by kelliekareen 4
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3
2006-10-20 11:39:25
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answer #4
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answered by barbara s 2
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3 classes :( 18 x 5 = 90 90/30= 3
2016-03-28 02:48:12
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answer #5
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answered by Anonymous
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You subtract 5 students from each of the existing 18 classes, so each is left with only 30 students (35 - 5 = 30).
5 removed students per class multiplied times 18 classes leaves 90 students needing a new class into which to be joined (5 x 18 = 90)
If those 90 students are divided into groups of 30, you'll need to create 3 new classes (90 divided by 30 = 3).
2006-10-20 11:45:15
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answer #6
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answered by alchemist0750 4
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First, take the total number of classes and multiply that by the number of students in each class (18*35=630 total students to put in classes) Now divide the 630 students by 30 (the reduced class sizes) to get 21. Now, subtract the orignial 18 classes and you will get 3 NEW classes to be formed.
2006-10-20 13:01:16
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answer #7
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answered by Jame 3
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3 more
2006-10-20 11:49:54
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answer #8
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answered by Eric H 4
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3 new classes
2006-10-20 11:37:50
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answer #9
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answered by [a][l][v][i][n] 1
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take 5 students from each class. that's 18 * 5 extra students. 90 extra students. 90/30 is 3. 3 extra classes
2006-10-20 11:39:40
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answer #10
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answered by NeRdYkId1101 3
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solve the equation 18 * 35 = (18 + x) * 30
2006-10-20 11:51:47
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answer #11
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answered by George C 3
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