any of these answers would be great.
2006-10-20 06:11:21 · 5 answers · asked by lmak13 1 in Science & Mathematics ➔ Mathematics
Hypercube: 16 vertices, 32 edges, 24 faces, 8 solids
HyperHypercube: 32 vertices, 80 edges, 80 faces, 40 solids.
HyperHyperHypercube: 64 vertices, 192 edges, 240 faces, 160 solids.
The number of vertices is a simple power of 2.
2 to the 4th (dimension) = 16...
Edges are calculated by doubling the previous dimension's number of Edges plus the previous dimension's number of Vertices. e(4)=e(3)*2 + v(3)
e(4) = 12 edges of a cube*2 + 8 vertices of a cube = 32 edges
Faces are likewise calculated by doubling the previous dimension's number of Faces plus the previous dimension's Edges. f(4)=f(3)*2 + e(3)
f(4) = 6 faces of a cube*2 + 12 edges of a cube = 24 faces
Repeat the process for the solid: s(4)=s(3)*2 + f(3)
s(4) = 1 solid of the cube*2 + 6 faces of a cube = 8 solids
2006-10-20 06:53:13 · answer #1 · answered by Mike S 6 · 2⤊ 0⤋
A hypercube has:
24 Faces, 32 Edges, and 16 Vertices
2006-10-20 06:17:14 · answer #2 · answered by Leah H 2 · 0⤊ 0⤋
a regular old hypercube is 24 faces, 32 edges, 16 vertices
2006-10-20 06:14:55 · answer #3 · answered by dan 4 · 1⤊ 0⤋
Hyper = More than defalt amount so a hyper-hepercube is a hyper-cube with an extra dimention basically.
I can't remember how mnay side you find on it though.
2006-10-20 06:30:13 · answer #4 · answered by Anonymous · 0⤊ 0⤋
can not answer this question you need to specify the dimension of the hyperspace where the cube resides.
2006-10-20 07:22:47 · answer #5 · answered by gjmb1960 7 · 0⤊ 0⤋