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2006-10-20 03:19:11 · 5 answers · asked by Somebody 2 in Science & Mathematics Mathematics

5 answers

Put a point in (0,-5)
Put a point in (-2.5,0)

Joint the two points with a line.

2006-10-20 03:28:33 · answer #1 · answered by Dr. J. 6 · 0 0

well i cant draw on this thing but basically anything in the form,

f(x)=mx+c, is a straight line (linear) with gradient, m, and y-intercept, c. when i say y-intercept, this is the same as f(x) intercept here.

here we have gradient = -2 and y-intercept = -5

basically the graph is a straight line going "downwards", gradient = -2 means that "for every 2 you go across (to the right), it goes down 1" (very bad definition). it will cross the x-axis when f(x)=0, i.e. when, 0 = -2x-5, so x=-5/2. try plotting values of x and f(x) according to the equation to understand. your x-axis should go from left to right, and your f(x) - axis from 'down to up'.

2006-10-20 03:29:37 · answer #2 · answered by tsunamijon 4 · 0 0

Draw your axis.
Put one point at (0, -5) and another at (1, -7)
Join the two points with a ruler.

The End.

Alternately, use an online graphing applet, or a graphing calculator.
http://www.coolmath.com/graphit/index.html

2006-10-20 04:04:12 · answer #3 · answered by Leah H 2 · 0 0

Use mathlab / mathmatica to get a nice graph

2006-10-20 03:49:48 · answer #4 · answered by The Potter Boy 3 · 0 0

you need a texas instrument calculator to graph that one. I try to draw it on this site.
..O............1.............
.-3..-2..-1..0..1..2..3.. for x-xis
.......O......-1.............
................-2.............
............O.-3..............
................-4..............
.................O.............
.................-6..............
.................-7.O.........
.................-8..............
.................-9.....O.....

for y-axis
I hope this helps down two and right one

2006-10-20 03:50:17 · answer #5 · answered by missy 4 · 0 0

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