Put a point in (0,-5)
Put a point in (-2.5,0)
Joint the two points with a line.
2006-10-20 03:28:33
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answer #1
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answered by Dr. J. 6
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well i cant draw on this thing but basically anything in the form,
f(x)=mx+c, is a straight line (linear) with gradient, m, and y-intercept, c. when i say y-intercept, this is the same as f(x) intercept here.
here we have gradient = -2 and y-intercept = -5
basically the graph is a straight line going "downwards", gradient = -2 means that "for every 2 you go across (to the right), it goes down 1" (very bad definition). it will cross the x-axis when f(x)=0, i.e. when, 0 = -2x-5, so x=-5/2. try plotting values of x and f(x) according to the equation to understand. your x-axis should go from left to right, and your f(x) - axis from 'down to up'.
2006-10-20 03:29:37
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answer #2
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answered by tsunamijon 4
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Draw your axis.
Put one point at (0, -5) and another at (1, -7)
Join the two points with a ruler.
The End.
Alternately, use an online graphing applet, or a graphing calculator.
http://www.coolmath.com/graphit/index.html
2006-10-20 04:04:12
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answer #3
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answered by Leah H 2
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Use mathlab / mathmatica to get a nice graph
2006-10-20 03:49:48
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answer #4
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answered by The Potter Boy 3
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you need a texas instrument calculator to graph that one. I try to draw it on this site.
..O............1.............
.-3..-2..-1..0..1..2..3.. for x-xis
.......O......-1.............
................-2.............
............O.-3..............
................-4..............
.................O.............
.................-6..............
.................-7.O.........
.................-8..............
.................-9.....O.....
for y-axis
I hope this helps down two and right one
2006-10-20 03:50:17
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answer #5
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answered by missy 4
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