2006-10-20 03:02:49 · 8 answers · asked by Somebody 2 in Science & Mathematics ➔ Mathematics
5(a-2) -1 =5a-10-1 =5a-11
2006-10-20 03:05:21 · answer #1 · answered by . 3 · 0⤊ 0⤋
f(a-2) = 5a - 11
You substitute a-2 for x in the original equation.
f(a-2) = 5(a-2) - 1 = 5a -10 - 1 = 5a - 11
2006-10-20 10:06:58 · answer #2 · answered by Leah H 2 · 0⤊ 0⤋
all you have to do sustitute a-2 for x and simplify
so, f(a-2) = 5(a-2)-1 = 5a-10-1 = 5a-11
2006-10-21 02:01:26 · answer #3 · answered by grandpa 4 · 0⤊ 0⤋
simply subsitute x ---> a-2
so f(a-2) = 5(a-2) - 1
=5a - 10 -1
=5a - 11
2006-10-20 10:06:27 · answer #4 · answered by Stuart T 3 · 0⤊ 0⤋
put a-2 where ever you see x
f(a-2)=5(a-2)-1=5a-11
2006-10-20 10:08:07 · answer #5 · answered by sydney m 2 · 0⤊ 0⤋
5(a-2)-1
5a-10-1
5a-11 is your answer
im just a kid helping a stranger with math homework. sigh.
2006-10-20 11:45:57 · answer #6 · answered by Dukefrom7th 3 · 0⤊ 0⤋
treat x as = a-2
u ll get ur answer
i think at least u have hat much brain
asking simple questions
maths is not for u
2006-10-20 12:36:15 · answer #7 · answered by talk_2_ayush 2 · 0⤊ 0⤋
5Xa-2
2006-10-20 10:09:31 · answer #8 · answered by TMAC 5 · 0⤊ 0⤋