The question is number 9 following this pdf link http://bmat.org.uk/downloads/BMAT_Introductory_Specimen_Paper.pdf
Can someone please expalin how you work out this question to get the answer E(300N) and what formulae are used? Thanks
2006-10-20 02:42:28 · 4 answers · asked by Jack R 1 in Science & Mathematics ➔ Physics
This is a problem in leverage, Force times distance is key here, the piston is 4 cm from the pivot, the pedal is 20 cm from the pivot. Therefore the force on the piston is multiplied 5 times 5 times 60 is 300.
2006-10-20 03:10:18 · answer #1 · answered by SteveA8 6 · 0⤊ 0⤋
The sum of the moments (force times distance) in a system should add up to zero so:
60(16+4) = F(4)
F=15*20 = 300N
2006-10-20 11:28:43 · answer #2 · answered by spoon_bender001 2 · 0⤊ 0⤋
408 + 140 = 548 mins
now......
divide 548 mins by 60
which = 9.13333333333333333333333333333 hrs
= 9.13 hrs a week (2 d.p)
2006-10-20 16:11:05 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Learn to spell SCIENCE
2006-10-24 00:13:36 · answer #4 · answered by Brown_Sugar 3 · 0⤊ 0⤋