x=2.5
(4^2.5)-(4^2.5-1)=(4^2.5)-(4^1.5)=24
2006-10-19 20:22:16
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answer #1
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answered by peachymoon02 2
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4^x - 4^x-1 =24
4^x-1 (4-1) = 24
4^x-1 *3 = 24
4^x-1 = 24/3
4^x-1 = 8
2^2(x-2) = 2^3
2x-2 = 3
2x = 5
x = 2.5
2015-12-19 11:36:18
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answer #2
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answered by PHAGU M 2
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4^x - 4^(x-1) = 24
Take note that 4^(x-1) = 4^x times 4^(-1)
And since 4^(-1) = 1/4......
4^x - (1/4) 4^x = 24
(3/4) 4^x = 24
4^x = 24 (4/3) = 32
Since 4 = 2^2 and 32 = 2^5
2^(2x) = 2^5
Hence
2x = 5
x = 2.5 ANS
Hope this helps
2006-10-19 20:36:13
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answer #3
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answered by scyxav 2
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4^x - 4^(x - 1) = 24
Factor out 4^x
4^x (1 - 4^-1) = 24
Simplify
4^x = 24/(3/4)
Simplify
4^x = 8 · 4
Thus,
4^x = 32
Make them powers of 2
2^2x = 2^5
Equate the exponents
2x = 5
Thus,
x = 5/2 = 2.5
^_^
2006-10-19 23:46:04
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answer #4
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answered by kevin! 5
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4^x - 4^(x-1) = 24
Now 4^(x-1) = 4^x.4^1= 4^x/4
So 4^x - 4^(x-1) = 4^x - 4^x/4
= 3.4^x/4 = 24
Thus 4^x = 24*4/3
= 32
4^x = (2²)^x = 2^(2x) = 32 = 2^5
ie 2x = 5 Thus x = 5/2 (=2.5)
Check
4^(5/2) - 4^(5/2 -1) = 2^5 - 2^3 = 32 - 8 = 24
2006-10-19 20:30:40
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answer #5
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answered by Wal C 6
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Notice that 4^x = 4^(x-1) * 4. Factor 4^(x-1) out of both terms on the left hand side, and you're well on your way.
For the rest, it will help to notice that 4 = 2^2.
2006-10-19 20:26:29
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answer #6
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answered by Hal 2
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4^x - 4^x-1 =24
4^x-1 (4-1) = 24
4^x-1 = 8
2^2x-2 = 2^3
2x-2 = 3
2x = 5
x = 2.5
2006-10-19 20:26:51
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answer #7
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answered by ooyesoui_0014 2
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The answer is dude 2.5
2006-10-19 20:31:06
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answer #8
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answered by UtAkArSh 2
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x = 2.5
I solved it with intuition. What if the answer had not been so neat? I'd probably rewrite it as
f(x) = A^x - B^(x-Q) - C = 0
And then use Newton's method or Danby's method to find the roots.
g(x) = exp(A) A^x - exp(B) B^(x-Q)
repeat until x converges:
x(i+1) = x(i) - f(x)/g(x)
That's an iterative method, though. Not an analytic one.
2006-10-19 20:23:30
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answer #9
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answered by David S 5
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2.5
2006-10-19 21:51:34
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answer #10
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answered by Anonymous
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2.5
2006-10-19 20:23:25
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answer #11
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answered by Anonymous
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