The length of a card is three times as long as its width. The perimeter is 264 inches. What are the dimensions of the card?
2006-10-19 17:18:20 · 10 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Let the width be x.
Then the length must be 3x.
The perimeter is two times the length, plus two times the width.
In other words, the perimeter is 8x.
If 8x = 264, then x = 264/8 = 33.
Hence, the card has a length of 99 and a width of 33.
2006-10-19 17:27:16 · answer #1 · answered by Bramblyspam 7 · 1⤊ 1⤋
If the width = w,
then the length is = 3w
Perimeter is the distance right round a shape. This shape is a rectangle (since one side is longer than the other) with 4 sides (2 lenghts and 2 widths)
So Perimeter = 3w + 3w + w + w = 264
6w + 2w = 264
8w = 264
w = 264/8
w = 33
The dimensions therefore are
width = w = 33 inches
Length = 3w = 3X33 = 99 inches
To Check:
Perimeter = 99 + 99 + 33 + 33 = 264!
2006-10-19 20:49:08 · answer #2 · answered by Loral 2 · 0⤊ 1⤋
perimeter = 2x + 2y
say x = width
say y = length
length = 3 x width
y = 3x
Equation 1; 2x + 2y = 264
Equation 2; y = 3x
by substitution to equation 1;
2x + 2y = 264 ; since y = 3x
2x + 2(3x) = 264
2x + 6x = 264
8x = 264
x = 264/8
x = 33
therefore;
if width is = 33 inches the length would be = 3(33) = 99
width is = 33 inches
legnth = 99 inches
2006-10-19 17:28:38 · answer #3 · answered by caveman0101 1 · 1⤊ 1⤋
Length is 99 and width is 33
2006-10-19 17:28:23 · answer #4 · answered by suzyQ 3 · 1⤊ 1⤋
Think of this: If the length is 3 times the width, the same applies to the dimensions! If you know the parameter, you've got it!
2006-10-19 17:21:05 · answer #5 · answered by WJ 7 · 1⤊ 0⤋
well, kinda logical, but if u want it to be solved using algebra, then so be it
let x be the width, therefore the length is 3x
perimeter = x + 3x + x + 3x
8x = 264
x = 33
therefore, the width is 33 inches, the length is 3x33 = 99 inches
2006-10-19 17:25:49 · answer #6 · answered by michael 2 · 1⤊ 1⤋
L=3W
P=264=2L+2W
264=2(3W) +2W
264=8W
W=33
L=3(33)
L=99
2006-10-19 17:27:55 · answer #7 · answered by thenewzepplin 1 · 1⤊ 1⤋
suppose its width is x
lenght=3x
perimeter=2*(length+breadth)
2*(x+3x)=264inches
2*4x=264
4x=264/2=132
therefore x=132/4=33inches
therefore lenght =33*3=99inches
dimensions=33inches and 99inches
2006-10-19 19:14:29 · answer #8 · answered by Twarita 2 · 0⤊ 1⤋
x=3y, 2x+2y=264
2(3y)+2y=264
8y=264
y=33
x=99
hope it helps
2006-10-19 17:30:26 · answer #9 · answered by x x 1 · 1⤊ 1⤋
33 BY 99 INCHES
GOD BLESS
2006-10-19 17:21:34 · answer #10 · answered by thewindowman 6 · 1⤊ 1⤋