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And if Newton theory of gravitation was not exact ,why did Einstein use His Universal G constant in his Field Equation expression?

2006-10-19 17:03:05 · 3 answers · asked by goring 6 in Science & Mathematics Physics

Per Einstein Field equation isnt the Newton Universal gravity constant represent the ratio of space curvature to the 4 vectors Tensor?

2006-10-20 04:15:49 · update #1

If G is invariant for macromasses ,then why is it different for micromasses?

2006-10-20 04:28:39 · update #2

3 answers

the unit for G is N m2 kg-2
N-force
m2-area
kg-2-mass

2006-10-19 17:16:50 · answer #1 · answered by Anonymous · 0 0

universal G a constant lol like we put x for unknown values we use G in physics for gravitational constant small g is 9.8n/m detailed explanation The gravitational constant, denoted G, is an empirical physical constant involved in the calculation of the gravitational attraction between objects with mass. It appears in Newton's law of universal gravitation and in Einstein's theory of general relativity. It is also known as the universal gravitational constant, Newton's constant, and colloquially Big G.[1] It should not be confused with "little g" (g), which is the local gravitational field (equivalent to the free-fall acceleration[2]), especially that at the Earth's surface; see Gravity of Earth and Standard gravity. According to the law of universal gravitation, the attractive force (F) between two bodies is proportional to the product of their masses (m1 and m2), and inversely proportional to the square of the distance (r) between them:

2016-05-22 04:23:07 · answer #2 · answered by Michelle 4 · 0 0

To find units of the gravitational constant, you must first take an equation where its present:
Eg. F = G (m1 x m2)/r^2
where F = force of attraction of the two bodies
G = gravitational constant
m1 = mass of first body
m2 = mass of second body
r = distance between the two bodies.

Now, F = G(m1 x m2)/r^2
i.e G(m1 x m2) = F r^2
i.e G = F r^2/(m1 x m2)
F is measured in Newtons, r in metres, m in kg
Therefore G's units are N m^2/kg^2
i.e N m^2 kg^-2

2006-10-19 21:45:07 · answer #3 · answered by Alan 2 · 0 0

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