2(n squared) is the formula for maximum number of electrons per principle quantum number (or energy level) therefore
1st is 2 (only has s subshell)
2nd is 8 (has s and p subshells)
3rd is 18 (has s,p, and d subshells)
4th is 32 (has s,p,d, and f subshells)
5th is 50 (has s,p,d,f and g subshells)
6th is 72 (has s,p,d,f,g, and h subshells)
7th is 98 (has s,p,d,f,g,h, and i subshells)
Now electons do not fill shells entirely but rather in a pattern filling lower, more stable energies first.
s carries 2 electrons, p orbitals max out at 6, d maxes out at 10, f at 14, g at 18, h at 22, and the i subshells can hold up to 26 electrons.
2006-10-19 15:29:05
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answer #1
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answered by piercesk1 4
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8
2006-10-19 15:23:22
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answer #2
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answered by Luke T 2
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How many possible electrons can be held in the n=8 energy level?
2016-06-22 05:24:51
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answer #3
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answered by ? 1
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maximum number of electron in the outermost shell = 2*n^2
with n as the number of the shell
2016-09-08 16:18:02
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answer #4
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answered by Anh 1
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What's the accepted quantum number for the fourth quantum shell
2015-09-30 03:44:08
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answer #5
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answered by Anonymous
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depends on the number of nucleons and ionization potential. from there, electron configutation levels can be determined. remember,, the outer shell can contain a maximum of 8 electrons for monatomic elements. compounds can be more challenging.
2006-10-19 15:21:13
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answer #6
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answered by Anonymous
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s level - 2
p level - 6
d level -10
f level - 14
each of these sublevels has orbitals which hold 2 e- each. s has 1, p has 3, d has 5, and f has 7. the numbers that go before these are the levels.
2006-10-19 15:24:22
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answer #7
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answered by palm_of_buddha 3
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how can we find that?
I mean what is the way to find it?
Thanx
2016-02-22 05:58:26
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answer #8
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answered by ? 1
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