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if x > 0 and y >0 prove that:

(x/y) + (y/x) > or = 2

use a geoetry proof



i need helpp

2006-10-19 14:27:01 · 3 answers · asked by alex 1 in Education & Reference Homework Help

3 answers

We start with the observation that the square of any real number is ≥ 0. Since x-y is a real number, we have:
(x-y)²≥0
Expand the squared term:
x²+y²-2xy≥0
Add 2xy to both sides:
x²+y²≥2xy
Since both x and y are stipulated to be positive, we can divide by xy without changing the inequality. This gives us:
x/y + y/x ≥ 2

As required.

2006-10-19 15:14:01 · answer #1 · answered by Pascal 7 · 0 0

since numbers greater than 0 are 123456789 etc
substitute the values for instance x=2,y=2
u get 2/2+2/2=2
because 2/ is 1and 2/2 is also 1 u add which gives u 2.
GOOD LUCK.no matter the number is still the same

2006-10-19 21:31:41 · answer #2 · answered by Val 2 · 0 1

x and y =1

(1/1)+(1/1)=2

duh

2006-10-19 21:30:08 · answer #3 · answered by The infamous bongblaster 4 · 0 1

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