What is the sum of the digits in a+b
2006-10-19 13:45:21 · 3 answers · asked by evogregoire@sbcglobal.net 1 in Education & Reference ➔ Homework Help
The correct answer is 2002. I'll show you why....
2^5 = 32 (Two digits)
5^5 = 3125 (Four digits)
Total of six digits
2^6 = 64 (Two digits)
5^6 = 15625 (Five digits)
Total of seven digits
If you keep doing this, you'll realize that the total number of digits is equal to one greater than the power. The power is 2001; therefore, there are 2002 digits.
2006-10-19 14:07:35 · answer #1 · answered by Josh 2 · 1⤊ 0⤋
2^2001 has about 601 digits.
2^10 has 4 digits, 2^20 has 7 digits, 2^30 has 10 digits, etc. That makes the formula for the number of digits 1+3*2001/10=601.3
5^2001 has about 1401 digits.
5^10 has 7 digits, 5^20 has 14 digits, 5^30 has 21 digits, etc. This formula is 7*2001/10=1400.7
601+1401=2002
2006-10-19 14:14:29 · answer #2 · answered by Scott K 2 · 1⤊ 1⤋
7^2001. When digit are ADDED, their power remain the same.
2006-10-19 13:47:54 · answer #3 · answered by greenwhitecollege 4 · 0⤊ 1⤋