Help me with these three problems please.
Use this formula...
F=9/5C+32
Please show all work.
1) If the Celsius is 456, what would be the Fahrenheit?
2) If the Celsius is 15, what would be the Fahrenheit?
3) If the Celsius is (-55), what would be the Fahrenheit?
Please Help.
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2006-10-19 12:29:10 · 5 answers · asked by cat 3 in Science & Mathematics ➔ Mathematics
Just plug in C (Celsius) into the equation and solve for F (Fahrenheit)
F = (9/5)C + 32
1) F = (9/5)(456) + 32
9 * 456 = 4104
4104 / 5 = 820.8
820.8 + 32 = 852.8
456°C = 852°F
2) F = (9/5)(15) + 32
9 * 15 = 135
135 / 5 = 27
27 + 32 = 59
15°C = 59°F
3) F = (9/5)(-55) + 32
9 * -55 = -495
-495 / 5 = -99
-99 + 32 = -67
-55°C = -67°F
To double check, you can go to Google and type '456 C in F' or '15 C in F' or '-55 C in F'.
2006-10-19 12:31:07 · answer #1 · answered by Puzzling 7 · 0⤊ 0⤋
Math Help..?
Use this formula...
F=9/5C+32
1) If the Celsius is 456, what would be the Fahrenheit?
*F=(456*9/5+32=852.8
2) If the Celsius is 15, what would be the Fahrenheit?
*F=15*9/5+32=59
3) If the Celsius is (-55), what would be the Fahrenheit?
-55*9/5+32=67
2006-10-19 12:35:36 · answer #2 · answered by raj 7 · 0⤊ 0⤋
1)F=9/5(456)+32
F=820.8+32
F= 852.8
2)F=9/5(15)+32
F=27+32
F=59
3)F=9/5(-55)+32
F=-99+32
F=-67
2006-10-19 13:23:15 · answer #3 · answered by lubna h 1 · 0⤊ 0⤋
Just plug in C into the equation and solve for F...
F = (9/5)C + 32
1) F = (9/5)(456) + 32
456 * 9 = 4104
4004 / 5 = 820.8
820.8 + 32 = 852.8
2006-10-19 12:39:35 · answer #4 · answered by craftyboy 2 · 0⤊ 0⤋
fahrenheit is Celsius x (9/5) + 32
2006-10-19 12:32:11 · answer #5 · answered by Chelsea Nicole 1 · 0⤊ 1⤋