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the original equation was (x)(3x-1)=100
and i got down to
3x^2-1x-100=0

and i can't figure out how to do the rest
can someone pls help?

and i'd really appreciate if you can explain/write out the whole thing rather than just the answer

thanks so much!

2006-10-19 12:07:21 · 9 answers · asked by Anonymous in Education & Reference Homework Help

please, anyone? i really need help with this!

2006-10-19 12:12:20 · update #1

sorry sparkle, thanks for trying but the parentheses mean multiplication not addition

i really appreciate the help though!

2006-10-19 12:15:42 · update #2

9 answers

Greta is right, you need to use the quadratic equation. However, she wrote down the equation wrong (you're supposed to divide by 2a instead of 4ac).

(-b+-sqrt(b^2-4ac))/2a

a = 3
b = -1
c = -100

(1+-sqrt((-1)^2-4*(3)*(-100)))/(2*3)

x = 5.94
x = -5.61

Those are the two solutions.

2006-10-19 12:22:24 · answer #1 · answered by Josh 2 · 1 0

the above answer is wrong since when you multiply x by x you get x^2

you're doing everything write

You put it in standart form, which is halfway done

Ax+By + C

Then you have to use a quadratic formula

x= -b +/- √b^2 - 4ac
4ac

A = 3 B= -1 C = -100

Plug it all in

x= -1 +/- √-1^2 - 4(3)-100
4(3)

then do it both ways one time with a plus other with a minus

x= -1 +/- √1 + 1200
12

x= -1 +/- √1201
12

then do it both ways one time with a plus other with a minus

x= -1 + 34.655
12
x= 2.805

x= -1 - 34.655
12

x= -2.971

2006-10-19 19:17:20 · answer #2 · answered by Greta J 2 · 0 1

Basically you have got the first step right. The next thing is to used quadratic equation to solve it:

x =-b+-sqrt(b^2-4ac))/2a

where
a = 3
b = -1
c = -100

x = (1+-sqrt((-1)^2-4*(3)*(-100)))/2(3)

Using the above equation, you should be able to solve the entire problem. I won't go in depth so that you can try it on your own

2006-10-19 20:21:32 · answer #3 · answered by Clown & Joker 5 · 0 1

actually when u expand the equation u get: 3x^2-x=100
then if u going to solve this the final equation should be
3x^2-x-100=0
therefore after using quadratic equation u should get x=10.17 or x= -9.83

2006-10-20 22:28:12 · answer #4 · answered by smileefacee_2 1 · 0 0

i'm not sure but here's what i got

(x)(3x-1)=100

1. You add the x's together so that's 4x-1=100
2. Then you want the get 4x alone, so you add to to both sides
4x-1=100
+1 + 1
3. Then you get 4x=101
4. Then you divide 4 from each side
5. So x=25.25

2006-10-19 19:12:38 · answer #5 · answered by sparkle311588 1 · 0 3

You have it in the form of a quadratic equation and so you can just use the quadractic formula to solve it.

For a quadratic equation of the form ax^2 + bx + c = 0
the formula is:

x = (-b +/- squareroot(b^2 - 4ac)) / 2a

For you equation I think the values for x are 5.94 and -5.61 but please check these. (Josh is right)

2006-10-19 19:28:45 · answer #6 · answered by Matisse 2 · 1 1

Hey, Are you trying to solve for X....because 3x^2-1x-100 is far as you can go, in factoring..that ...

2006-10-19 19:23:27 · answer #7 · answered by Anonymous · 0 2

Don't forget to put your answer back in to see that it actually works (great way to see which of these answers is correct)

2006-10-19 19:28:24 · answer #8 · answered by FlCpa 3 · 0 1

woah your right our avatars do look a lot alike.

2006-10-19 19:21:25 · answer #9 · answered by Anonymous · 1 1

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