A constant torque of 10m-N is applied to a 10kg uniform disk of radius .20m. What is the angular speed of the disk after it rotates 2.0 revolutions from rest?
2006-10-19 11:36:34 · 2 answers · asked by lubna h 1 in Science & Mathematics ➔ Physics
please show the work for the problem.
2006-10-19 13:13:08 · update #1
First, compute the moment of inertia of the disk. Second, apply the formulas analagous to F=ma. These formulas should be in your textbook. The moment of inertia is analagous to mass, the torque is analagous to force, and the acceleration---that's intermediate. You don't really need to know that. It can be solved by energy, too. The work is force applied through two revolutions (that's like W=fs), and final energy is calculated by moment of inertia and angular speed. Like kinetic energy is calculated by mass and velocity (K.E.=1/2 mv^2). Look at the linear example; rotational is closely analagous to it.
2006-10-19 11:49:50 · answer #1 · answered by Anonymous · 0⤊ 0⤋
just like F=ma, torque equals rotational inertia times angular accel.
2006-10-19 19:35:28 · answer #2 · answered by kemchan2 4 · 0⤊ 0⤋