physics help!!!?

1 ⤊

A 35kg child sits on a uniform seesaw of negligible mass, 2.0m from the fulcrum/pivot point. Another child (30kg) must sit how far form the fulcrum for the seesaw to be in equlibrium?

2006-10-19 11:33:43 · 3 answers · asked by lubna h 1 in Science & Mathematics ➔ Physics

3 answers

torque = f x r

So if f1 = 35kg * g
and f2 = 30 kg * g
then r1must be (30/35) * r2

Hence, the distance is 2.333 meters.

2006-10-19 11:37:41 · answer #1 · answered by Professor Beatz 6 · 1⤊ 0⤋

35*2=30x
70=30x
x=2.3m

2006-10-19 18:37:57 · answer #2 · answered by Troy J 3 · 0⤊ 0⤋

That's too easy... did you REALLY have to ask this question?

2006-10-19 18:41:38 · answer #3 · answered by skypiercer 4 · 0⤊ 2⤋