(XL/ X) + XVI - XIX = please rewrite the problem with answer in roman numerals and regular numbers.
2006-10-19 10:36:58 · 15 answers · asked by Olivia 3 in Science & Mathematics ➔ Mathematics
No probs
XL = 40, X = 10, XVI = 16 and XIX = 19.
So (XL/X) + XVI - XIX
= (40/10) + 16 - 19
= 4 + 16 - 19
= 1
= I (in Roman numerals)
ie (XL/X)+ XVI - XIX = I
2006-10-19 10:38:06 · answer #1 · answered by Wal C 6 · 0⤊ 1⤋
Xl Roman Numeral
2016-10-01 04:03:57 · answer #2 · answered by ? 4 · 0⤊ 0⤋
1 I
2006-10-19 10:39:21 · answer #3 · answered by deadlypotent 2 · 0⤊ 0⤋
(XL / X) + XVI - XIX =
40/10 + 16 - 19 =
1 = I
Th
2006-10-19 10:39:18 · answer #4 · answered by Thermo 6 · 0⤊ 0⤋
(XL/X)+XVI-XIX = (40/10)+16-19 = 4+16-19 = 1= I
2006-10-19 10:40:37 · answer #5 · answered by Anonymous · 0⤊ 0⤋
(40 / 10) + 16 - 19 = 1
2006-10-19 10:40:18 · answer #6 · answered by DanE 7 · 0⤊ 0⤋
XL = 40
X = 10
XVI = 16
XIX = 19
40/10 + 16 - 19
= 4 - 3
= 1 aka I
2006-10-19 10:42:26 · answer #7 · answered by Leah H 2 · 0⤊ 0⤋
40
2016-03-28 01:51:39 · answer #8 · answered by Anonymous · 0⤊ 0⤋
In regular numbers, it's
(40/10) + 16 -19 or 27.
The answer in Roman numerals is XXVII.
2006-10-19 10:41:35 · answer #9 · answered by steiner1745 7 · 0⤊ 1⤋
40(XL) DIVIDE BY 10(X) + 16(XVI) - 19(XIX)= 1(I)
2006-10-19 10:43:14 · answer #10 · answered by hamboy_612000 2 · 0⤊ 0⤋