What values for x must be excluded in the following fraction?
x+2 / x^2-9x+14
2006-10-19 09:54:38 · 3 answers · asked by Anonymous in Education & Reference ➔ Homework Help
I'm assuming that you mean [x+2]/[x^2-9x+14].
Since you can't devide by '0', you determine the values of x that would make the denominator = 0.
therefore, solve for x^2-9x+14 = 0
HINTS.
the results would be (X+ ?)(X+ ??) = 0
since the product of ?*?? is 14, then they probably are 1 & 14 or 2 & 7. The sign in front of 14 is '+'. It indicates that the numbers must be both + or -. One cannot be + and the other -. If the sign was '-' then one would be + and the other -.
Also their sum is -9.
If you add -2 + -7 you get -9.
That would make x-2 = 0 OR x-7 = 0. So, the values of x cannot be either +2 or +7. If they are, then the denomintor would be 0.
2006-10-19 10:23:52 · answer #1 · answered by SPLATT 7 · 1⤊ 0⤋
=2/x^2+x-9x+14
=2/x^2-8x+14
since x^2 is in the denominator,x=0 should be excluded
2006-10-19 16:58:08 · answer #2 · answered by relaxedbhavica 2 · 0⤊ 0⤋
your moral values
2006-10-19 18:12:53 · answer #3 · answered by screaming frenzy 5 · 0⤊ 0⤋