2006-10-19 08:32:36 · 8 answers · asked by Ryan 1 in Science & Mathematics ➔ Mathematics
Length = 3 * Width
so perimiter is 3W + W + 3W + W or 8W
so 8W = 264
so Width = 33
and Lenth = 99
2006-10-19 08:38:41 · answer #1 · answered by Jim R 3 · 1⤊ 0⤋
Perimeter Formula
P = 2L + 2W
264 = 2(3W) + 2W
264 = 8W
264/8 = 8W/8
33 = W
Insert the W value into the equation
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P = 2L + 2W
264 = 2(99) + 2(33)
264 = 198 + 66
264 = 264
The width is 33 inches
The length is 99 inches
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2006-10-19 09:02:01 · answer #2 · answered by SAMUEL D 7 · 0⤊ 0⤋
Perimeter of a card = Perimeter of a rectangle = 2(L + B)
Let the length of the card = L
Let the breadth of the card = B
Therefore,
L = 3B ....(A)
264 = 2(L + B)
L + 3L = 132
L = 33
B = 11
Therefore, the dimensions are L = 33 units & B = 11 units
(Please note: - If no dimensions are provided, ensure that you write units after each dimension)
2006-10-19 08:38:33 · answer #3 · answered by aazib_1 3 · 0⤊ 2⤋
Perimeter/2 = perimeter of length + perimeter of width = 132
132/4 = 33(width)
132-33 = 99(length)
final answer: 99x33
2006-10-19 08:40:54 · answer #4 · answered by mrspankyj 1 · 0⤊ 0⤋
l = 3w equation 1
2w + 2l = 264 equation 2
substitution of equation 1 into equation 2 yields
8w = 364
so w = 33 inches and l = 99 inches
2006-10-19 08:40:23 · answer #5 · answered by ? 7 · 0⤊ 0⤋
p=264=2l+2w
l=3w
264=2(3w)+2w
264=8w
w=33
l=3w=99
check
p=2l+2w=2*99+2*33=198+66=264
2006-10-19 08:39:41 · answer #6 · answered by yupchagee 7 · 0⤊ 0⤋
You haven't specified the shape of the card. It could be triangular... or pentagonal .... or just about any number of 2D shapes, provided they're not of equal-length sides.
2006-10-19 08:38:47 · answer #7 · answered by Anonymous · 0⤊ 2⤋
33in x 99in
2006-10-19 08:42:42 · answer #8 · answered by alyskim 3 · 0⤊ 0⤋