6x to the second power -5xy-4y to the second power. if x is 2 and y is negative 2 .
2006-10-19 06:13:16 · 9 answers · asked by baby girl 123 1 in Science & Mathematics ➔ Mathematics
whats your question? you have everything just plug in the numbers
2006-10-19 06:15:38 · answer #1 · answered by Anonymous · 0⤊ 0⤋
(6x)^2 - 5xy -4y if x=2, y= -2
First put in x and y where they belong
==> [6(2)]^2 -5(2)(-2) -4(-2)
Then Solve.
==>[12]^2 - 10(-2) -(-8)
==> 144 + 20 +8
==>144+28
==>172
2006-10-19 13:19:09 · answer #2 · answered by Shanna J 4 · 2⤊ 0⤋
you have 24 + 10 - 4=30
2006-10-19 13:26:30 · answer #3 · answered by justpristine 2 · 0⤊ 0⤋
1.) 6*(2) all to the second power
12 to the second power
144
2.) (-5(2)(-2) - 4(-2)) all to the second power
(20 - (-8)) "
(28) "
784
2006-10-19 13:22:17 · answer #4 · answered by J G 4 · 0⤊ 0⤋
6(2^2) - 5(2)(-2) - 4((-2)^2) =
6(4) - (-20) - 4(4) =
24 +20 -16 =
28 --> Final Answer
2006-10-19 13:38:35 · answer #5 · answered by shortcut78 1 · 1⤊ 0⤋
6x^2-5xy-4y^2
6*2^2-5*2*(-2)-4(-2)^2
24+20-16
28
2006-10-19 15:10:34 · answer #6 · answered by yupchagee 7 · 0⤊ 0⤋
Haha. So many different answers. I got the same as shortcut. 28.
final answer.
2006-10-19 13:50:42 · answer #7 · answered by Miss E. 2 · 0⤊ 0⤋
(6*2)^2-5*2*-2-(4*-2)^2
or (12)^2+20-(-8)^2
or 144+20-64
=228
2006-10-19 13:26:49 · answer #8 · answered by DaMiEn S 2 · 0⤊ 0⤋
JG is right based on what you typed...are you subtracting the quantities or adding the quantities?
2006-10-19 14:21:11 · answer #9 · answered by csulbalgebra 2 · 0⤊ 0⤋