d/dx (ln[x + y]) where x and y are both variables
2006-10-19 05:47:20 · 5 answers · asked by benabean87 2 in Science & Mathematics ➔ Mathematics
d/dx (ln[x + y]) = 1/(x+y) * d/dx(x+y)
= 1/(x+y) * 1 + 0
= 1/(x+y)
2006-10-19 05:50:04 · answer #1 · answered by BEN 2 · 0⤊ 0⤋
no,not partial differentiation,but differentiation of implicit
functions
the d/dx of (ln!x+y!)=[1/(x+y)][1+dy/dx]
2006-10-19 12:50:39 · answer #2 · answered by raj 7 · 0⤊ 0⤋
when you write "d/dx", you have already assumed that y is a constant with respect to the differentiation. So no, just take the derivative with respect to x.
2006-10-19 12:50:26 · answer #3 · answered by Eulercrosser 4 · 0⤊ 0⤋
Yes. Treat "y" as a constant, since all you are only looking for "x/dx".
2006-10-19 13:10:41 · answer #4 · answered by Dave 6 · 0⤊ 0⤋
You can use implicit instead
2006-10-19 12:54:17 · answer #5 · answered by Anonymous · 0⤊ 0⤋