Can anyone tell me what the chances/odds are that a nut full house is beat by a royal flush in tx holdem? Before everyone gets their cracks in, I know a RF beats a FH everytime, but what I mean is what is the chances that one player will have the nut FH and the other a RF? It happened to me last night, it sux. Come on math wizards surely one of you knows how to do the math on this.
2006-10-19 05:05:52 · 3 answers · asked by Got2seeit 2 in Science & Mathematics ➔ Mathematics
9 players at the table
2006-10-19 05:33:23 · update #1
The probability of drawing a royal flush with seven cards is 3,216 : 1.
The probability of drawing a full house with seven cards is 37.5 : 1
Now it gets complicated because you share 5 of the cards.
I don't want to figure it out, but the 1:3200 pretty much overshadows everything else.
Good luck next time. You have to play your cards, if someone beats you with a better hand, that's poker.
2006-10-19 05:31:19 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Here's the problem with us math wizards, or at least this one, I need more information. One easy piece of information should be how many players are at the table?
Enjoy your next time playing TX Holdem. :)
2006-10-19 05:10:46 · answer #2 · answered by SmileyGirl 4 · 0⤊ 0⤋
the chance is 99.9 %
2006-10-19 05:07:31 · answer #3 · answered by Mario 2 · 0⤊ 0⤋