2006-10-19 04:48:00 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
6ab - ab= 5ab
I'm not sure what you mean by the second?
Do you mean:
cuberoot(9a²+b²) = (9a²+b²) ^(1/3)
or
(cuberoot(9a)² + b)²?
2006-10-19 04:52:55 · answer #1 · answered by Mariko 4 · 0⤊ 2⤋
To simplify 6ab - ab, we note that the two terms are like terms, and just add/subtract the coefficients. 6ab - 1ab = 5ab.
There is no way to simplify the cube root of (9a² + b²), sorry.
2006-10-19 11:54:17 · answer #2 · answered by Jay H 5 · 0⤊ 0⤋
6ab - ab is the same as 6ab - 1ab because multiplying by 1 doesn't change anything.
So, 6ab - 1ab = 5ab just subtract the numbers in front of the variables.
The second part I'm not sure exactly what you are trying to write and so I'm not sure what to do with that problem.
-Hope this paritally helps. :)
2006-10-19 11:51:01 · answer #3 · answered by SmileyGirl 4 · 0⤊ 0⤋
6ab - ab = 5 ab
because ab is 1ab
in the second part
9a whole squared + b whole squared = 3a square + b square
2006-10-19 12:07:59 · answer #4 · answered by talk_2_ayush 2 · 0⤊ 0⤋
6ab-ab=5ab
(9a^2+b^2)^1/3
2006-10-19 12:01:11 · answer #5 · answered by raj 7 · 0⤊ 0⤋