2006-10-19 04:39:48 · 5 answers · asked by Homer H 2 in Science & Mathematics ➔ Mathematics
f'(x) = 4995 * -1 * (1+.12COS(x))^-2 * 0.12 * -sin(x)
= 599.4 * (1+0.12cos(x))^-2 * sin(x)
2006-10-19 04:43:46 · answer #1 · answered by BEN 2 · 0⤊ 0⤋
Since the numerator is constant we can use the
reciprocal rule. Also, the differential, dy, is
the derivative of the function times dx.
So
dy = -4995*(-.12 sin x)/(1 + .12 cos x) ^2 dx.
2006-10-19 11:55:21 · answer #2 · answered by steiner1745 7 · 0⤊ 0⤋
well you can pull the 4995 out because its a constant
then you have 1/(1+.12cos(x)) .
the derivative of that is
-(.12sin(x))/((1+.12cos(x))^2)
final answer= {-4995*.12sin(x)}/[{1+.12cos(x)}]^2
2006-10-19 11:49:16 · answer #3 · answered by Jack 1 · 0⤊ 0⤋
F(x)= 4995/(1+.12 cos x)
F'(x)= [(1+.12 cos x)*0 - 4995*(.12(-sin x))]/(1+.12 cos x)²
F'(x)= (599.4 sin x)/(1+.12 cos x)²
2006-10-19 11:44:04 · answer #4 · answered by Mariko 4 · 0⤊ 0⤋
wow wow :O thats like the mostf*@#ed up peoce of maths i have ever seen but i ma take a guess and say 2
2006-10-19 11:43:00 · answer #5 · answered by Anonymous · 0⤊ 3⤋