You should get a parabola, opening upwards, that crosses the y-axis at (0, -1), and with a vertex at (1, -3).
Plotting the point with x value of 1 should give you (1, -3),
and plotting the pt w/ x value of -1 should give you (-1, 5), not (-1, 3)
(because 2(-1)² -4(-1) -1 = 2 + 4 - 1 = 5).
Hope that helps! :)
2006-10-19 04:45:44
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answer #1
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answered by Jay H 5
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When x = -1, y = 5
y = 2x^2-4x-1
y = 2(-1)^2-4(-1)-1 when you square -1 it becomes positive
y = 2(1)-4(-1)-1
y = 2+4-1
y = 2+3
y = 5
When x = 1, y = -3
y = 2x^2-4x-1
y = 2(1)^2-4(1)-1
y = 2(1)-4(1)-1
y = 2-4-1
y = 2-5
y = -3
plot these values you should get a parabola that opens upward, with a minimum value at (1,-3)
( x y)
(-1 5)
(-.2247, 0)
(1,-3) minimum
(2,-1)
(2.2227,0)
(3,5)
2006-10-19 12:11:18
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answer #2
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answered by Pam 5
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When x = 1:
y = 2(1)^2 - 4(1) - 1
y = 2 - 4 -1
y = -3
When x = -1:
y = 2(-1)^2 - 4(-1) - 1
y = 2 + 4 - 1
y = 5
So your points should be (1, -3) and (-1, 5). It looks like (1, -3) is the vertex of the parabola, when you graph it. See the link below...
2006-10-19 11:45:37
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answer #3
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answered by PM 3
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When x = -1
y = 2(-1)^2 -4(-1) - 1 = 2(1) + 4 - 1 = 5
When x = 1
y = 2(1)^2 - 4 (1) - 1 = 2 - 4 - 1 = -3
2006-10-19 11:50:36
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answer #4
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answered by p_ne_np 3
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-1 = x means
y = 2(-1)^2 - 4(-1) -1
y = 2*1+4-1
y = 2+4-1
y = 6-1
y = 5
(-1,5) is one point
+1 = x means
y = 2(1)^2 - 4(1) -1
y = 2*1 - 4 -1
y = 2-4-1
y = -2-1
y = -3
(1,-3) is the second point.
Hope this helps. Good luck with graphing. :)
2006-10-19 11:54:21
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answer #5
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answered by SmileyGirl 4
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Should be a parabola -
Coordinates -
(-2, 15) (-1, 5), (0, -1), (1, -3), (2, -1)
For y=2x^2-4x-1
2006-10-19 11:46:02
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answer #6
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answered by Anonymous
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when x=-1 y=5
when x=1 y=-4
2006-10-19 11:41:33
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answer #7
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answered by raj 7
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I get (-1,5) and (1,-7)
2006-10-19 11:44:51
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answer #8
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answered by rwbblb46 4
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