Please solve the equation and show work so that I can see if I am doing the problem correctly.
2006-10-19 04:37:10 · 11 answers · asked by Rhonda O 1 in Science & Mathematics ➔ Mathematics
√x³ = 27
√x³ = 3³
√x = 3
x = 9
2006-10-19 04:41:00 · answer #1 · answered by BEN 2 · 1⤊ 0⤋
If you are asking for the cube roof of 27, the answer is 3. And there is a simple way to find it. Since 27 = 9*3, and 9 = 3*3 , so 27 = 3*3*3.
2006-10-19 05:05:53 · answer #2 · answered by Anonymous · 0⤊ 0⤋
answer is 9: here is how
the problem is x to the power 3/2 =27
so x=27 to the power of 2/3
i.e square of cube root of 27
i.e square of 3
which is 9
2006-10-19 04:48:02 · answer #3 · answered by grandpa 4 · 0⤊ 0⤋
√x³ = 27 square both sides
x^3=729 take cube root of both sides
x=9
2006-10-19 08:33:17 · answer #4 · answered by yupchagee 7 · 0⤊ 0⤋
square both sides to get rid of the radical
then you have x^3 = 27^2 (do the math)
take the cubed root of both sides and
then you have x = ?
2006-10-19 04:44:35 · answer #5 · answered by Emery 1 · 0⤊ 0⤋
Do your own math homework lol but the cubed root of 27 is 9
2006-10-19 04:45:05 · answer #6 · answered by xx_lush_xx 3 · 0⤊ 2⤋
x^3=27*27
x^3=729
x=cube root of 729
x=9
2006-10-19 04:52:21 · answer #7 · answered by kenyanmartin2000 2 · 0⤊ 0⤋
squaring both sides we get ,
x^3=27^3
=729
therefore x=cuberoot of 729>>>got it!!
2006-10-19 05:42:37 · answer #8 · answered by DaMiEn S 2 · 0⤊ 0⤋
to sparkling up through logarithms 9^x=27 => log?(9^x) = log?(27) given log(a^n) = nlog(a) => xlog?(9) = log?(27) => x = log?(27)/log?(9) => x = log?(3³)/log?(3²) => x = 3log?(3)/(2log?(3)) => x = 3/2
2016-12-05 00:11:54 · answer #9 · answered by gerrit 4 · 0⤊ 0⤋
x=9 now you figure out why
2006-10-19 04:42:25 · answer #10 · answered by Anonymous · 0⤊ 0⤋