Assume the variable diff has already been declared. Write an expression whose value is the address of diff .

Question

i seem to not understand what this is asking

yes, it is C/C++.

and that did answer my question

Answer 1

Is the C/C++?

"&diff" represents the address of diff

Hope that helps

Answer 2

it means that you should assign a pointer to the variable "diff"...the expression that represents the address of "diff" is : &diff
it reserves a memory location,and you can access the variable "diff" by its address.good luck!

Answer 3

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