it is not a sequence therefore for this there is no nth formula
2006-10-19 03:04:18
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answer #1
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answered by shagun 2
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It's the Fibonacci sequence: 2 - 3 - 5 - 8 - 13 - 21 - 34 - 55 - 89 - 144 .......
You get each number, adding the 2 before...
2 + 3 = 5
3 + 5 = 8
5 + 8 = 13... and so on...
The nth : 89
2006-10-19 03:15:50
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answer #2
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answered by rocy_77 2
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The nth term formula for the above sequence is n = (n - 1) + (n - 2)
2006-10-19 04:39:07
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answer #3
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answered by aazib_1 3
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This is the Fibonacci sequence which has the closed form:
F(n) = (f^n - (1-f)^n ) / sqrt(5), where f=1/2 + 1/2 sqrt (5) = golden ratio.
2006-10-19 03:20:22
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answer #4
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answered by cordefr 7
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If a the nth number and b the number before in the series then a=b/1.61
2006-10-19 09:06:02
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answer #5
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answered by Mathew C 5
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This is the Fibonacci sequence. It's ubiquitous.
2006-10-19 03:05:03
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answer #6
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answered by jack b 3
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its most easily defined recursively by the difference formula:
u_n=u_(n-1)+u_(n-2)
where u_n is the nth term.
2006-10-19 03:08:05
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answer #7
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answered by tsunamijon 4
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If this is your homework, there are 2 rules. One, either you add to the next digit by one higher than you have added to the previous digit, or you add to the next digit the digit behind it.
2006-10-19 03:06:29
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answer #8
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answered by Anonymous
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fn = [((1 + (51/2))/2)n + ((1 - (51/2))/2)n] / (51/2)
2006-10-19 03:05:35
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answer #9
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answered by Brian L 7
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12,17,23,30,38
it is 38
ht
2006-10-19 03:04:25
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answer #10
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answered by Henry_Tee 7
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