Please help???

Question

x^2+2x-15/4x^2 divide x^2-25/2x-10

Answer 1

x^2+2x-15/4x^2 divided by x^2-25/2x-10 can be rewritten as:
x^2+2x-15/4x^2 * 2x-10/x^2-25

Step 1: Factor both fractions
x^2+2x-15/4x^2 = (x+5)(x-3) / 4x^2
2x-10/x^2-25 = 2(x-5)/(x+5)(x-5) - note: a^2 - b^2 = (a+b)(a-b)

Step 2: Multiply factored fractions:
(x+5)(x-3) / 4x^2 * 2(x-5)/(x+5)(x-5)
(x+5) and (x-5) cancels on both sides:
(x-3) * 2 / 4x^2
x-3 / 2x^2 (solution!)