The sum of two numbers equals 39 and the difference is 17 what are the two numbers?

Question

Please show how you arrived at the answer. Thanks

Answer 1

x + y = 39
x - y = 17
gives

2x = 56 (by adding the two equasions together)
x = 28

y = 11

Answer 2

39 and 17 are your solutions. I did it like a dis: the version is 22. shall we initiate with the first digit (2). What 2 numbers plus eachother ='s 6, with a distinction of two. 4 & 2. So now the (20). What 2 numbers = 50?.... no longer something Now decrease back as a lot as (2). we want an yet another pair that has a 6 because the a million'st digit. 9 & 7? definite! Now that ='s 16 so subtract 16 from 56...40. What 2 2 digit numbers = 40 with a distinction of 20? 30 & 10! There you flow. Now upload them up. 39+17=56 Sorry if it truly is too a lot information yet it is how I did it.

Answer 3

Let one of the numbers = x and the other number = y.

Then we have the equations: (1) x + y = 39 and (2) x - y = 17.

These are two simultaneous equations. To solve, take (2) from (1). This gives 2y = 22 and hence y = 11.

You know that x + y = 39 so x + 11= 39. Hence x = 28

Check 28 - 22 = 17 OK

Answer|: the two numbers are 11 and 28

Answer 4

let the smaller number = x, and the larger number = x + 17

the sum of them = 39 so

(x) + (x + 17) = 39

x + x + 17 = 39

2x + 17 = 39

subtract 17 from both sides

2x + 17 - 17 = 39 - 17

2x = 22

divide both sides by 2

x = 11

That is the answer for the smaller number. Now remember we made the larger one = x + 17?

so, to find the larger one, just sub 11 into the equation

= 11 + 17

= 28

Therefore the two numbers are 11 and 28

Hope that helped :)

Answer 5

39 - 17 = 22

22 / 2 = 11

11 + 17 = 28

11 + 28 = 39 now stop messing about.

As fore the other answers. Algebra's really not necessary. You'll be working your change out at the co-op with it next.

Answer 6

sum equals 39 > k + m = 39, > k = 39 - m
difference is 17 > k - m = 17, > k = 17 + m

so 39 - m = 17 + m
i,e, 39 - 17 = m + m
22 = 2m

so, m = 11, > k = 39 - 11 = 28

Yeah!

Answer 7

let the 2 numbers be x and y
x+y = 39
x-y = 17
adding the above equations
2x = 56 so x =28:since x-y =17, if x is 28, y = 28-7 =11
i.e. the 2 numbers are 28 &11
checkback
x+y = 28+11 = 39
x-y = 28-11 = 17 i.e ans is correct

Answer 8

let x & y be any two numbers ,then x+y =39...........1
x-y=17.............2

x+y=39
x-y=17
2x=56
x=56\2
x=28
now put x=28 in equation 1
28+y=39
y=39-28
y=11

Answer 9

Let's call the first number 'cat' and the second 'dog'. So,

cat + dog = 39 and
cat - dog = 17

Let's create a 3rd equation by adding the left hand side and right hand side of the above two equations, thus:

cat + dog + cat -dog = 39 + 17

i.e. 2 x cat = 56. So, cat must be 28.

Now take any of the first two equations (e.g. cat - dog = 17) to calclulate dog, e.g. 28 - dog = 17. Therefore dog must be 11.

I love cats and dogs!

Answer 10

28 and 11

Answer 11

39 - 17 = 22

22 divided by 2 = 11

So, 11 + (11+17)

= 11 and 28