English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

If a = 2 + i, then in the form a + bi, what does a^-1 equal? In this problem i represents the imaginary number square root of -1.

2006-10-19 00:38:11 · 6 answers · asked by Sasha 2 in Science & Mathematics Mathematics

6 answers

This is the answer:


1/(2+i) = (2-i)/{(2-i)*(2+i)}

(2-i)/(4-i^2) = (2-i)/5

2/5 - i/5

2006-10-19 01:01:07 · answer #1 · answered by tsunamijon 4 · 0 0

Given: a=2+i
a^-1=(2+i)^-1
=1/(2+i)
Multiply by (2-i)/(2-i):

a^-1=(2-i)/(2+i)(2-i)
=(2-i)/(4-i^2)
=(2-i)/(4-(-1^-1/2)(-1^1/2)
=(2-i)/4-(-1)
=(2-i)/(4+1)
=(2-i)/5
=2/5-i/5
=2/5+(-1/5i)

2006-10-19 11:59:44 · answer #2 · answered by tul b 3 · 0 0

Extra credit? I don't think so. I'm not doing any more of your homework and I would advise everyone else not to help you either. You neither appreciate help nor accept critisism.

DO YOUR OWN HOMEWORK.

Then you can just go ahead and report me. They already know about you.

2006-10-19 08:15:57 · answer #3 · answered by Anonymous · 0 0

1/(2+i)

(2-i)/(2-i) * 1/(2+i)

(2-i)/(4-i^2)

(2+i)/5

2/5 + i/5

2006-10-19 07:57:47 · answer #4 · answered by bob h 3 · 0 0

Clarify ....
What do you mean with "then in the form a + bi" ?
For a correct answer |i need that info.

2006-10-19 09:24:33 · answer #5 · answered by gjmb1960 7 · 0 0

http://www.coolmath.com/

http://www.aplusmath.com/

2006-10-19 07:51:52 · answer #6 · answered by Anonymous · 0 0

fedest.com, questions and answers