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The difference of the differences of the squers of any two consequtive numbers is " a static" number always. Numbers considered are the simple whole numbers on the number line generelly used in arithematics. What is it ? Simple but difficult question, should be answered within 24 hours.

2006-10-19 00:35:27 · 14 answers · asked by rameshrpukale 2 in Science & Mathematics Mathematics

14 answers

It's always 2....... And alsooo the consecutive differences of squares of two consecutive numbers are always consecutive odd numbers.....

2006-10-19 00:55:00 · answer #1 · answered by gangtom 2 · 0 0

let the first number be defined as x and the second one as y, where x and y are whole numbers and y=x+1.

then, Y^2 - X^2 = (Y - X)(Y + X)
since Y=X+1 => (X + 1 - X)(Y + X)
=> (1)(Y+X)
this is the mathematical proof that the difference of the squares of two whole numbers is equal to the sum of the numbers

as for the other answers you have to be careful and do not make mistakes when working with negative number ( the 2a+1 example )

2006-10-21 12:45:53 · answer #2 · answered by Guilherme L 1 · 0 0

enable x be the extra beneficial form and y the smaller. Then: x - y = 3 x^2 - y^2 = 39 y = x - 3 So x^2 - (x - 3)^2 = 39 x^2 - x^2 + 6x - 9 = 39 6x = 40 8 x = 8 to verify: y = 5 8^2 = sixty 4, 5^2 = 25 and sixty 4 - 25 = 39 as required = A

2016-12-08 17:18:28 · answer #3 · answered by ? 4 · 0 0

It's "2" the difference of the differences of the squares of two consecutive numbers.
eg: 2^2-1^2=3
3^2-2^2=5
5-3=2

2006-10-19 01:19:27 · answer #4 · answered by Cephalic 3 · 0 0

The difference of the the squares of any two consecutive numbers is the sum of the two mumbers.

But what you have asked is something else which I don't understand. Maybe you meant the 'difference of the differences' of the squares of three consecutive numbers. In this case, the answer is two.

2006-10-19 04:52:43 · answer #5 · answered by Anonymous · 0 0

This question is in the form of b^2-a^2 where b=a+1.

b^2-a^2=
(a+1)^2-a^2
a^2+2a+1-a^2
2a+1

so that answer is that you take the smaller number double it and add one.

Exmaple Let a=5 and b=6 accourding to the formula the answer should be 2(5)+1=11

b^2-a^2=
6^2-5^2
36-25
11

2006-10-19 00:46:53 · answer #6 · answered by Anonymous · 0 0

the sum of the 2 numbers

2006-10-19 03:56:57 · answer #7 · answered by sushobhan 6 · 0 0

if n is the smaller number,
the next consecutive number is n+1
so square of (n+1) = nsquare+2n+1
square of n = nsquare
so difference = 2n+1
so the answer for
difference of the differencesof any two consecutive numbers is
2 times the smaller number plus one

2006-10-19 07:00:10 · answer #8 · answered by grandpa 4 · 0 0

choose two consecutive numbers

a+b and a+b+1

squares are a^2+2ab+b^2 and a^2+b^2+ 2ab +2a +2b +1
difference between squares is 2a+2b+1

now choose two different consecutive numbers
a+c and a+c+1

the difference between the difference of the squares is
|2b-2c| independent of a.

now set b=0 ...

2006-10-19 01:10:52 · answer #9 · answered by Anonymous · 0 1

the difference will be the sum of the two numbers.

2006-10-19 03:15:27 · answer #10 · answered by Anonymous · 0 0

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