What is the value of g at a distance of five times the Earth's radius?

Question

The value of g at the Earth's surface is about 9.8 m/s2.

Answer 1

g(R) = 9.8m/sec^2
g(5R) = g(R)/25
g(5R) = 0.392 m/sec^2

Answer 2

gravitational force of attraction at the earths surface=(k*m1*m2)/R^2=g for 1kgm1
gravitational force of attraction at 6R (5R from the surface)=(k*m1*m2)/(6R)^2=g2 for a 1kgm1.
the g2 gravitational force is 9.8/36=.2722m/sec^2

Answer 3

I suspect it would depend on how far out in the Mojave dessert you, your wife and the kids have traveled before someone looks at the gas gauge and she says, GEE, I THOUGHT YOU FILLED THE TANK !!! lol