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A Greengrocer has two baskets of lemons each containing 30 lemons that have remained near the end of the days trading. He was selling lemons from the 1st basket at 2 for a $1 and lemons from the 2nd basket at 3 for $1. This equates to $15 earned from the 1st and $10 from the 2nd basket...a total of $25 from both.
He then decides to merge the contents of the remaining two baskets into one and sell the remaining 60 lemons at 5 for $2. Even though he is still selling 5 for $2 (3 for $1 + 2 for $1 as previously sold), he will now only earn $24.
What happened to the other $1?

2006-10-18 19:22:46 · 4 answers · asked by Anonymous in Education & Reference Trivia

4 answers

It didn't go anywhere. It's all about the order in which you solve the problem. Follow the order of operations to solve the problem. Parenthesis, Exponents, Multiplication/Division, Adittion/Subtraction. If you solve the problem that way, the dollar went no where.

.additional note to what the person below me wrote..."15 batches of 2 and 10 batches of the 3 doesn't equal 12 batches of 5." That is true, however...the problem said "combined the remaing 60 lemons", which means he didn't sell any out of the first two baskets of thirty. So
15x2=30
10x3=30
add those two together 30+30=60 lemons
12x5=60


Another similar problem:

Three guys are walking late one night in the middle of Wyoming when they enter a small town with one hotel. Upon entering the hotel, they discover from the owner that the rent is $30 an night for a room. They search their pockets, srach up all thir loose change, and find out they have $10 each, so they deciede to rent one room all use it together. The owner takes their money, hands them the key, and they go to sleep.
After much thinking, the owner deceides he had charged the poor wanderers too much. He calls over a bellboy, hands him $5 to give back to the men. On his way, the bellboy thinks to himself:"how are three men going to split 5 dollars?" So he keeps $2 for himself, and gives each man $1 back.
Question: In the end, each man paid $10 but got $1 back, meaning each man only paid $9, for a total of $27. The bellboy has $2 more, for a total of $29. Where is the last dollar?

answer: Hotel $25.00
Bellhop $ 2.00
Customers $ 3.00
total $30.00

2006-10-18 19:53:07 · answer #1 · answered by imhalf_the_sourgirl_iused_tobe 5 · 1 0

It never existed. You can't average something that never happened and try to make it logical. He sold 60 lemons and got $24.00. If he had sold the 60 lemons the first way he would have gotten $25.00.
15 batches of 2 and 10 batches of the 3 doesn't equal 12 batches of 5.

2006-10-19 02:53:07 · answer #2 · answered by Thomas S 3 · 0 0

there is no missing doller...

The first time:
2 @ $1 = $0.50 average
3 @ $1 = $0.33 average

Total average is [(0.50+0.33)/2] is $0.4166 (rounded to 2 dp)

The second time:
5 @ $2 = 0.40 average

Difference of average is $0.4166 - $0.40 = 0.0166

Multiply that by 60 and you will get your "missing" dollar.

So first time round you sold the goods at higher price on average than you did second time around, hence you end up with less money....

2006-10-19 05:11:22 · answer #3 · answered by Zed 3 · 0 0

His average price for the first is 412/3 cents. His average price for the second is 40 cents

2006-10-19 02:37:08 · answer #4 · answered by Anonymous · 0 0

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