Let their age be x
so Kevin's age = x+5
total age = 2x+x+5 = 53 or 3x+5 = 53
x= 16
so ages are alex = 16; alicia (being twin) = 16; kevin = 16+5 = 21
2006-10-18 18:26:32
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answer #1
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answered by Mein Hoon Na 7
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Let a represent alex and alicia's ages
Kevin is five years older than the twins so his age is a+5
Taking all this into account , we get an equation
2a+a+5=53
3a+5=53
3a=48
a=16
Therefore Alex and Alicia are 16 years old while Kevin is 21
2006-10-19 03:25:05
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answer #2
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answered by Martinique Samuelson 5
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The twins are 16 and Kevin is 21.
a+ 2b = 53
a = b+5
b + 5 + 2b = 53
3b = 53 - 5 = 48
b = 48/3 = 16
a = b + 5
a= 16 + 5 = 21
2006-10-19 01:33:58
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answer #3
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answered by smarties 6
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Answer is 16.
x+5 +2x (the twins)=53 so 3x=53-5=48
48/3=16
2006-10-19 01:27:17
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answer #4
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answered by Nelson_DeVon 7
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Given
x=age of Alicia
y=age of Alex
z= age of Kevin
if
z=x+5
y=x
x+y+z=53
What is x?
Formula
x+y+z=53
x+y+x+5=53
x+x+x=53-5
3x=48
x=16
therfore:
Alicia and Alex are both 16
2006-10-19 05:06:10
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answer #5
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answered by Sherly 1
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let: x - the age of one of the twins...
x + 5 - the age of kevin
therefore,
53 = x + x + (x + 5)
53 = 3x + 5
48 = 3x
x = 16
therefore, the age of the twins is 16.
2006-10-19 01:36:06
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answer #6
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answered by emee_rocks 2
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suppose the age of the twins is x
then
2x+ x+5 = 53
or, 3x= 53-5
or,3x = 48
or, x= 48/3=16
twins are 16 years old
2006-10-19 01:30:35
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answer #7
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answered by Anonymous
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Alex = x
Alicia = x
Kevin = x + 5
Add them together and set it equal to 53.
3x + 5 = 53
3x = 48
x = 16
Alex and Alicia are each 16.
Kevin is 21.
2006-10-19 01:27:54
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answer #8
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answered by PatsyBee 4
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16 And 16 and 21!
2006-10-19 01:28:08
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answer #9
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answered by Echo 0 2
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$x = 53;
$y = $x - 5;
$a, $b = $y/3;
print "Alex and Alicia are $a, and kevin is " . ($c+5) . ".\n";
Alex and Alicia are 16, and kevin is 21.
2006-10-19 01:42:49
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answer #10
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answered by boter_99 3
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