6th grade math I cannot remember how to do!HELP?

Question

Problem: In a raffle, we have two items: car 3.00 a ticket. video game 2.00 a ticket. If on saturday we sold 80 tickets and made 203.00, how many car tickets did we sell?
Can you help me by telling me how to get to this answer? I need to explain the steps to my son:)

Answer 1

let the no of car tickets be x and videogame be y.
x+y=80 ---------------------------(1)
and
3*x+2*y=203--------------------(2)

to solve multiply (1) by 2 and subtract from (2).
x=203-160=43
and
y=80-x=37.

Answer 2

Let x be the no of car tickets and y be the no of videogame tickets.

On that day 80 tickets were sold.

So x+y=80

Total cost obtained by selling all tickets is 203.

Since cost of 1 car tkt is 3 and 1 videogame tkt is 2 ,we have

3x+2y=203.

Solving the 2 linear equations we get x=43 , y=37

Answer 3

sixty 5 x 6 = 390+ 50 x 11= 550= $940 truly, I in basic terms found out the conceivable additions there might want to be to get an end type of 40. I notwithstanding, properly the 50s are both going to be a mode with an ending of 00, or 50. After determining that if it were 0, the finished 65s extra up necessary might want to finally end up with an volume of timber below 17. then you definately comprehend this is an ending of fifty, for this reason the quantity of white spruces replaced into even. From there, you in basic terms try the possibilities until eventually you locate the staggering total. desire this helps :)

Answer 4

Define two variables. Lets call them
C = number of car tickets, and
V = number of video tickets.

Now we can use the information we were given to formulate two equations. The total number of tickets sold was 80, so:
C + V = 80.
The total money raised was $203, so:
3C + 2V = 203.

Hopefully your son is actually being taught how to solve equations like this and he can take it from there.
(C = 43, V = 37)

Answer 5

x = number of car tickets
y = number of video game tickets

x + y = 80

3x + 2y = 203

now do substitution - solve for one variable then plug it into other equation.

for example
x + y = 80
x = 80 - y

3x + 2y = 203
3(80-y) + 2y = 203
240 - 3y +2y = 203
-y = 203-240 = -37
y=37

x+y = 80
x+ 37 = 80
x = 80-37 = 43

so you sold 43 car tickets and 37 video game tickets

to check plug back in: 43 @ 3.00 = 129 and 37 @ 2.00 = 74 and 129 + 74 = 203 - so its all good

Answer 6

solution->first assume both are equal number of tickets
40 X 3 =120
40 X 2 = 80
----
200
difference between car and video game(price)=1
203-200=3
3/1=3
so 40 + 3 =43(car)
and 40 - 3 =37(video)

Answer 7

develop and equation
2 plus 3 = 5
80/5 = 16
16 = x

203 = (3x) + (2x)

48 car tickets
32 video game tickets

then multiply out for proof