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A ball at the end of a string of length 1.4 m rotates at a constant speed in a horizontal circle. It makes 5.9 rev/s. What is the period of the ball's motion? Answer in units of s.
part 2
What is the frequency of the motion? Answer
in units of Hz.
part 3
What is the ball's angular velocity? Answer
in units of rad/s.

2006-10-18 17:12:42 · 1 answers · asked by polo_05_polo 1 in Education & Reference Homework Help

1 answers

The trick here is to realize that it doesn't matter what the length of the string or the mass of the ball is.

1.) The period is the time it takes to make 1 revolution. 5.9 revolutions * sec = 1/5.9 rev/sec = 0.169 s.

2.) Frequency = 1/period = 5.9 Hz

3.) There are 2π radians per cycle. Thus, 5.9 Hz * 2π = 37.07 rad/s.

2006-10-19 02:01:03 · answer #1 · answered by ³√carthagebrujah 6 · 0 0

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