2006-10-18 16:14:48 · 9 answers · asked by Ryan Z 1 in Science & Mathematics ➔ Mathematics
x^2 = 2x + 3
x^2 - 2x -3 = 0
(x - 3) * (x + 1) = 0
x =3 or x = -1
2006-10-18 16:18:06 · answer #1 · answered by spongeworthy_us 6 · 0⤊ 0⤋
Algebraically, yoiu move the x^2 to the left side, giving you -x^2-2x+3. You can use the quadratic equation to solve it from here, using a=-1, b=2, and c=-3. A different approach (if you have a graphing calculator) is to put x^2 in Y1 and 2x+3 in Y2 , and see where they intersect. There is a function on TI-83 to calculate it exactly, which is to press 2nd calc, then five. Press enter three times and you have your answer.
2006-10-18 17:19:07 · answer #2 · answered by Ana L 2 · 0⤊ 0⤋
Change this to
x^2 - 2x - 3 = 0. Then, factor the equation as follows.
(x - 3)(x + 1) = 0. So x = 3 or x = -1.
2006-10-18 16:18:42 · answer #3 · answered by iuneedscoachknight 4 · 0⤊ 0⤋
Subtract 2x + 3 from both sides:
x^2 - 2x - 3 = 0
Then use the quadratic formula with:
a = 1
b = -2
c = -3
2006-10-18 16:19:18 · answer #4 · answered by Owlwings 7 · 0⤊ 0⤋
x^2 - 2x - 3 = 0
it's of the form (ax + c)( bx + d) = abx^2 + (bc+ad)x + cd
ab=1
c+d = -2
cd = -3
so c=1 and d=-3
(x + 1)( x - 3) = 0
solving x=-1 and x=3
2006-10-18 16:20:24 · answer #5 · answered by Anonymous · 1⤊ 0⤋
re-arange
X^2-2X-3=0
Factor it
(X-3)(X+1)=0
Answers
X=3 and X=-1 (they are both answers, must use both)
2006-10-18 16:19:09 · answer #6 · answered by CAMELS 2 · 0⤊ 0⤋
x^2-2x-3=(x-3)(x+1)=0
x=3 or -1
2006-10-18 16:17:26 · answer #7 · answered by raj 7 · 0⤊ 0⤋
subtract the x^2 to make it zero on one side then u can factor and use the zero product property or use the quadratic equation
DO U OWN DAM HW!
2006-10-18 16:17:02 · answer #8 · answered by Anonymous · 1⤊ 0⤋
x^2 type questions I can not solve.
2006-10-18 16:33:40 · answer #9 · answered by deepak57 7 · 0⤊ 0⤋