A 72 g baseball slides off of a 1.4 m high table and strikes the floor a horizontal distance of .67 m away from the table. The acceleration of gravity is 9.81 m/s^2.
What was the direction of the ball's velocity just before it hit the floor? That is, at what angle (in the range -90degrees to +90degrees relative to the horizontal directed away from the table) did the ball hit the floor?
2006-10-18 15:21:42 · 4 answers · asked by EXHILARATION 2 in Education & Reference ➔ Homework Help
Look, the only reason I posted this question is because I DON'T get it. My physics teacher did a bad job of explaining it. And when it asks for direction, it asks for the direction in degrees not "down" and that's the only part I don't know how to do. If you can't help me, don't comment. It's a waste of your time and space.
2006-10-19 08:46:28 · update #1
The time it takes the ball to reach the floor is given by h = .5*g*t^2; so t = √(2*h/g). In that time it has travelled d horizontally, so the horizontal velocity of the ball is vx = d/t
vx = d/√(2*h/g).
The vertical velocity is vy = g*t. Using the same t ,
vy = √2*g*h).
The angle at which it hits the floor is then arctan(vy/vx).
2006-10-18 15:32:42 · answer #1 · answered by gp4rts 7 · 0⤊ 0⤋
i dont want to do your homework for you.
but the definition of velocity is "speed in a given direction." so figure out the speed and direction.
2006-10-18 15:49:24 · answer #2 · answered by maiabell2 2 · 0⤊ 0⤋
down
2006-10-18 15:26:22 · answer #3 · answered by wanda s 2 · 0⤊ 0⤋
Do your own homework!
2006-10-18 15:29:57 · answer #4 · answered by smash_mouth_man2003 3 · 0⤊ 0⤋