English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

I really could use some help on this problem. Thanks for any help on this one!

A 75.0 kg ice skater moving at 9.50 m/s crashes into a stationary skater of equal mass. After the collision, the two skaters move as a unit at 4.75 m/s. If the impact time is 0.135 s, what are the magnitudes of the average forces experienced by each skater during the colllision?

a) What is the Force experienced by the moving skater?
b) What is the Force experienced by stationary skater?

2006-10-18 15:13:46 · 1 answers · asked by Amara 1 in Education & Reference Homework Help

1 answers

OK, start by writing down formulas:
F = ma
a = Δv/t

Step 1: Determine the acceleration for both skaters. Since both skaters have equal acceleration (4.75 m/s), you only need 1 calculation:
a = Δv/t = 4.75 m/s / .135s = 35.185 m/s^2

Step 2: Determine the forces, given mass and acceleration:
F = ma = 75.0 kg * 35.185 m/s^2 = 2640 N (solution!)

Both skaters have the same force, because they have the same mass, and the same change in velocity over the same time.

2006-10-19 02:25:15 · answer #1 · answered by ³√carthagebrujah 6 · 0 0

fedest.com, questions and answers